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What is the greatest common divisor of 36 and 60?

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To find the greatest common divisor (GCD) of 36 and 60, we start by determining the prime factorizations of both numbers.

The prime factorization of 36 is:

- 36 can be divided by 2, giving 18.

- 18 can be divided by 2, giving 9.

- 9 can be divided by 3, giving 3.

- Lastly, 3 can be divided by 3, yielding 1.

Thus, the prime factorization of 36 is \(2^2 \times 3^2\).

The prime factorization of 60 is:

- 60 can be divided by 2, giving 30.

- 30 can be divided by 2, giving 15.

- 15 can be divided by 3, giving 5.

- Finally, 5 is a prime number, yielding 1.

Thus, the prime factorization of 60 is \(2^2 \times 3^1 \times 5^1\).

Next, we identify the common factors between these two factorizations:

- For the prime number 2, the minimum exponent in both factorizations is 2.

- For the prime

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